电力系统分析代写 Power Systems Analysis代写 EE代写

QUIZ 1

EEE406 Power Systems Analysis

电力系统分析代写 INSTRUCTIONS TO CANDIDATES 1. This paper consists of 2 questions. Answer ALL questions. 2. Read the above information carefully to

INSTRUCTIONS TO CANDIDATES 电力系统分析代写

1. This paper consists of 2 questions. Answer ALL questions.

2. Read the above information carefully to ensure you have the correct and complete question paper.

3. Please follow the requirement of each section and upload all the hand written corresponding answers on the downloadable answer book provided.

4. Communication between candidates in any means is forbidden. Answers must be entirely individual candidate’s independent effort. If you are found sharing your solutions with other candidates, or suspected of doing so, you would be penalized accordingly.

5. Candidates are required to scan the answer book and upload it in Moodle Platform within 15 min after the completion of examination.

Question 1 [20 marks] 电力系统分析代写

The per unit bus data and bus admittance matrix for a three-bus power system are given in Table 1 and Y_bus respectively.

Assume the initial per unit voltage V₂ = 1.00Ð0⁰ and V₃ = 1.00Ð0⁰ . Determine the per unit voltage V₂ and V₃ (up to four decimal places) using Gauss-Seidel method by performing THREE (3) iterations. Using the latest bus voltages, determine the per unit slack bus apparent power (up to four decimal places). [CLO1-PLO2:C4](20 Marks)

Question 2 [20 marks]

A three-bus power system is shown in Figure 1. The bus voltages, impedances, power generated, real and reactive power demand indicated on the diagram are in per unit value. The per unit bus admittance matrix of the network is given by Y_bus . Calculate the voltage at BUS 2 and BUS 3 (up to four decimal places) by performing one iteration using Fast Decoupled Newton-Raphson method. [CLO1-PLO2:C4](20 Marks)

APPENDIX 电力系统分析代写

Jacobian Matrix

H_ii = − Q_i − |V_i|²B_ii

N_ii = − P_i + |V_i|²G_ii

M_ii = − P_i − |V_i|²G_ii

L_ii = − Q_i − |V_i|²B_ii

H_ij = −|V_i||V_j||V_ij| sin ( θ_ij + δ_j – δ_i )

N_ij = |V_i||V_j||V_ij| cos ( θ_ij + δ_j – δ_i )

M_ij = −|V_i||V_j||V_ij| cos ( θ_ij + δ_j – δ_i )  

L_ij = −|V_i||V_j||V_ij| sin ( θ_ij + δ_j – δ_i )

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